Tangent Line - Problem Solving on January 08, 2023 in Algebraic Functions, Derivative, Differential Calculus, Equation, Slope of the given Curve, Slope of the Tangent, Tangent Line with No comments y=x2-25 at the point (13, 12) Step 1: Get the derivative of y=x2-25 Apply the Derivative of Square Root Ruleddxu=12ududxdydx=12x2-25(2x)dydx=xx2-25 Step 2: Get the slope at point (13, 12)m=13132-25m=1312 Step 3: Using the point-slope form at point (13, 12)y-12=1312(x-13)y-12=1312(x-13)1212y-144=13(x-13)12y-144-13x+169=012y-13x+25=013x-12y-25=0 Final Answer: 13x-12y-25=0 Share: Email ThisBlogThis!Share to XShare to Facebook
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