Tangent line to the given curves at the given point of tangency on January 07, 2023 in Algebraic Functions, Derivative, Differential Calculus, Equation, Slope of the given Curve, Slope of the Tangent, Tangent Line with No comments y=x3(x-1)4 at the point (2, 8) Step 1: Find the Derivative by applying the Product of Two Factors Ruleddx(uv)=udvdx+vdudxdudx=3x2dvdx=4(x-1)3ddxuv=4x3x-13+3x2x-14 Step 2: Using the pointslope form at point (2, 8)y-8=44(x-2)y-8=44x-88y-44x-8+88=0y-44x+80=044x-y-80=0 Final Answer: 44x-y-80=0 Share: Email ThisBlogThis!Share to XShare to Facebook
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