Normal Line Equation to the curves at the given point of tangency on January 10, 2023 in Algebraic Functions, Derivative, Differential Calculus, Equation, Normal Line, Slope of the given Curve with No comments y=(x2-1)2 at the point (-2, 9) Step 1: Get the Derivative by Applying the General Power Ruleddx(cun)=cnun-1dudxdydx=2x2-12-12xdydx=4xx2-1 Step 2: Get the slope at point (-2, 9)m=4(-2)-22-1m=-8(3)m=-24 Step 3: Apply the Equation of Normal Line at point (-2, 9)y-y1=-1m(x-x1)y-9=--124(x--2)y-9=124(x+2)2424y-216=x+224y-216-x-2=0x-24y+218=0 Final Answer: x-24y+218=0 Share: Email ThisBlogThis!Share to XShare to Facebook
0 comments:
Post a Comment