The derivative of a Qoutient

Find the Derivative of: y=3x2+43

Step 1: Multiply both side by ddx 
dydx=ddx3x2+43


Step 2: Apply the Qoutient Rule
ddxuv=vddx(u)-uddx(v)v2

Given:
u=3
dudx=0
v=x2+43
dvdx=6x(x2+4)2


Solution:
dydx=(x2+4)0-36xx2+42x2+46
dydx=-18xx2+42x2+46
dydx=-18xx2+44


Final Answer: -18xx2+44
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