Solve for the Given Problem

Find the Derivative of: y=2-3x-2x2x+3

Step 1: Multiply both side by ddx 
dydx=ddx2-3x-2x2x+3


Step 2: Apply the Qoutient Rule
ddxuv=vddx(u)-uddx(v)v2


Given:
u=2-3x-2x2
dudx=-3-4x2
v=x+3
dvdx=1


Solution:
dydx=(x+3)-3-4x2-2-3x-2x21x+32


Final Answer: -2x2-12x-11x+32
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