Solve for the Given Problem on January 02, 2023 in Algebraic Functions, Derivative with No comments Find the Derivative of: y=2-3x-2x2x+3 Step 1: Multiply both side by ddx dydx=ddx2-3x-2x2x+3 Step 2: Apply the Qoutient Ruleddxuv=vddx(u)-uddx(v)v2 Given:u=2-3x-2x2dudx=-3-4x2v=x+3dvdx=1 Solution:dydx=(x+3)-3-4x2-2-3x-2x21x+32 Final Answer: -2x2-12x-11x+32 Share: Email ThisBlogThis!Share to XShare to Facebook
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