Problem Solving of Rectilinear Equation on January 12, 2023 in Algebraic Functions, Derivative, Differential Calculus, Equation, Horizontal Rectilinear Motion, Rectilinear Motion with No comments The path taken by a particle is a horizontal line as itmoves according to the law s=16t4-76t3-7t2+12t+1.At what time will its acceleration be equal to one?What its velocity at that time? Step 1: Get the Derivative of s=16t4-76t3-7t2+12t+1to get the velocity. v=23t3-72t2-14t+12 Step 2: Get the Derivative of v=23t3-72t2-14t+12to get the acceleration a=2t2-7t-14 Step 3: Equate the acceleration to oneAt what time will its acceleration be equal to one? 2t2-7t-14=12t2-7t-15=0(2t+3)(t-5)=0t=5 Step 4: When t=5 at v=23t3-72t2-14t+12What its velocity at that time? a(5)=23(5)3-72(5)2-14(5)+12a(5)=2503-1752-1392a(5)=2503-157a(5)=-2213 Final Answer: t=5, a(5)=-2213 Share: Email ThisBlogThis!Share to XShare to Facebook
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