Solving a Rectilinear Motion on January 11, 2023 in Algebraic Functions, Derivative, Differential Calculus, Equation, Horizontal Rectilinear Motion, Rectilinear Motion with No comments A particle moves horizontally according to the law s=13t3-12t2-12t+1. At what velocity is the particle moving when t=1? when will the particle come to rest and what is its acceleration at that time? Step 1: Get the derivative of s=13t3-12t2-12t+1 to get the velocityv=t2-t-12 Step 2: At what velocity is particle moving when t=1?v=(1)2-(1)-12v=-12 Step 3: Get the factor of the velocity equation,When will the particle come to rest?t2-t-12=0(t-4)(t+3)=0t=4 Step 4: What is its acceleration at that time?Get the derivative of velocity equation to get the acceleration t2-t-12a=2t-1 when t=4a=2(4)-1a=7 Final Answer: v=-12, t=4, a=7 Share: Email ThisBlogThis!Share to XShare to Facebook
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